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HELP!!!!! 3^2x+1=1/81
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this one is actually pretty easy with a few tricks.
\[3^{2x+1} = \frac{1}{81}\] \[3^{2x+1} = \frac{1}{3^4}\] \[3^{2x+1} = 3^{-4}\]
then I can cancel the 3s
yes, technically you are taking log(base 3) both sides :)
then its 2x+1=-4
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exactly!
sweet then solve from there!!
perfect, you've got it!
answer is
x=-5/2?
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let's see....... yes!
perfect ty
yw
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