Question

x^2+4x-12=0

Answer 1

\[x^2+4x-12=0\]\[(x-2)(x+6)=0\]can you finish it off ?

Answer 2

@dallascowboys1998

Answer 3

could you solve that by completing the square please

Answer 4

\[x^2+4x-12=0\]\[x^2+4x=12\]\[x^2+4x+4=12+4\]\[x^2+4x+4=16\]\[(x+2)^2=16\]\[(x+2)=±\sqrt{16}\]\[x+2=±4\]\[x=-2±4\]\[x=~~-6,~~2\]

Answer 5

thank you

Answer 6

x^2-8x+15=0 solve by completing the square please