Question

Maria is comparing the prices of two window cleaning companies. Company A charges $6 per window and an additional $12 as service charges. Company B charges $5 per window and an additional $15 as service charges.

Answer 1

I jst helped u

Answer 2

no ik sorry my internet gets slow when theres so many comments

Answer 3

what are you trying to figure out?

Answer 4

Part A: Write equations to represent Company A and Company B's total charges for cleaning a certain number of windows. Define the variable used in the equations. (4 points)

Part B: Which company would charge less for cleaning 8 windows? Justify your answer. (3 points)

Part C: How much money is saved by using the services of Company B instead of Company A to clean 6 windows? (3 points)

Answer 5

A: 12+6x
B: 15+5x

x= amt of windows cleaned

Answer 6

I understand @geekfromthefutur

Answer 7

A: 12+48= $60
B: 15+40= $55

Company B is cheaper

Answer 8

A: 12+36= $48
B: 15+30= $45

you save $3

Answer 9

there you go... hope this helps

Answer 10

thank you (: can u help me with a few more

Answer 11

sure

Answer 12

ok thank you :3

Answer 13

Emily uses her college photocopier machine to photocopy at the rate of $0.08 per page. She decides to rent a photocopier machine for $90 a year. The cost of photocopying using the rented machine is $0.03 per page.

Part A: Write an inequality that can be used to calculate the number of pages that Emily should photocopy in a year so that the amount she pays for the rented machine is less than the college machine. Define the variable used. (5 points)

Part B: How many pages should Emily print in a year to justify renting the photocopier? Show your work. (5 points)

Answer 14

90+0.03x < 0.08x

part B may take a while

Answer 15

ok take your time (:

Answer 16

mkk

Answer 17

u still there @elementwielder

Answer 18

ya

Answer 19

90+0.03(1800)=0.08(1800)

Answer 20

oh ok is that part B ?

Answer 21

yes

Answer 22

simplified that would be 144=144

Answer 23

oh ok thanks dude your the best this math i freken suck at this lol

Answer 24

no i suck... this is just easier for me

Answer 25

and your welcome anytime

Answer 26

ok so its 90+0.03(1800)=0.08(1800) and i then say simplified that would be 144=144 right?

Answer 27

ya

Answer 28

oh thx bro hey can u help me with 2 more im really sorry iv im wasting any of your time >.<

Answer 29

nah i have plenty of time...

Answer 30

oh thx bro (;

Answer 31

your welcome...

Answer 32

In a certain town the temperature, x in degrees Celsius on a certain day is described by two statements:


If 3 times the temperature is increased by 2, the temperature is still less than 14°C.
Twice the temperature minus 7 is greater than -11°C.


Part A: Create a compound inequality to represent the temperature range. (3 points)

Part B: Can the temperature in this town be 5°C? Justify your answer by solving the inequalities in Part A. (3 points)

Part C: The average temperature in another town is 3°C but the actual temperature is within 4°C of the average. Write and solve an inequality to find the range of temperature in this town. (4 points)

Answer 33

Part A: Solve C = 5 over 9 (F - 32) for F. (4 points)

Part B: Determine the value of F when C = 8 °C. (2 points)

Part C: Solve –np – 80 > 60 for n. Show your work. (4 points)

Answer 34

-11 < 2x-7 or 3x+2 < 14

Answer 35

NO... 3(5)+2>14
simplified: 17>14

Answer 36

-1 is less than or equal to X is less than or equal to 7

Answer 37

those 3 above are four the 1st section of questions

Answer 38

oh ok thanks bro :3

Answer 39

\[C =\frac{ 5 }{ 9\times(F -32) }\]

Answer 40

multiply F to both sides
solve right side: \[\frac{ 5 }{ 288 }\]
divide C to both sides...

\[F=\frac{ 5 }{ -288C }\]

Answer 41

you can solve B from there...
im not sure how to do C

Answer 42

oh ok so the first question u said C= 5 over 9 x (F -32) is for part A right jw

Answer 43

ya under your last post the following 2 of my posts were for part A

Answer 44

oh ok thx

Answer 45

(;

Answer 46

your welcome sorry i couldnt help you out with Part C

Answer 47

its cool thanks tho (:

Answer 48

your welcome...

Answer 49

hey i was wondering how do i divide C from both sides?

Answer 50

for?

Answer 51

for part B i was trying to figure out how 2 divide C from both sides

Answer 52

well i have that set up a few messages up... so you dont need to do the hard work

Answer 53

oh ok thx :3

Answer 54

your welcome... lol

Answer 55

oh ok thts all the questions thank you so much for all the help :)

Answer 56

your welcome anytime im on or not on just ask and ill answer asap

Answer 57

oh ok thx :3

Answer 58

welcome