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solve 3sin^2(θ) - 4sin(θ) - 4 = 0?
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Two questions: http://imgur.com/SQsaRmO.jpg Help would be much appreciated! If I could get the steps or tips on how to,, it would be more than enough! Thanks! :-)
treat sin theta as t, so you have 3t^2 -4t -4=0, solve for t, then plug back to get theta
the same for the second part, just manipulate a little bit on cos (2 theta) = 1-2sin^2 (theta),
@Loser66 - I am trying to figure out how to do that.. Could you please help? I'm trying to factor but I can't figure it out. :(
use quadratic formula, not factor
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