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Solve the quadratic equation x^2 - 4x + 57 = -5 by completing the square. A.x=1±i√50 B.x=2±√58 C.x=2±i√58 Dx=2±√62
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\[ x^2 - 4x + 57 = -5\Rightarrow x^2 - 4x +4-4+ 57 = -5\Rightarrow\\ \Rightarrow (x - 2)^2-4 + 57 = -5\Rightarrow (x-2)^2=-58\]
\[x-2=\pm i\sqrt{58}\Rightarrow x=2\pm i\sqrt{58}\]
@John_ES is correct. Well Done!
thank you !
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