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solve using the quadratic formula. please help me people. x^2-4x-7=0
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\[(-b \pm \sqrt{b2-4ac})/2a\]
here in this case a =1, b = -4 and c = -7
?
If you have time, see http://www.khanacademy.org/math/algebra2/polynomial_and_rational/quad_formula_tutorial/v/using-the-quadratic-formula for how to do this problem
I'm sorry, but I'm not going to have time.
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What are the awnsers good sir?
huh?
just follow the formula what else do you want?
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