Question

Solve the quadratic equation. 3x^2 = 27
A. x = 3 and x = 27
B. x = 1 and x = 9
C. x = ±3
D. x = ±√3

Answer 1

c

Answer 2

27 /3=9. the sqrt of 9 is -3 and 3

Answer 3

Hello Awesome_Naya ,

To find x, take square root both sides :

\(\sqrt{3x^2} = \pm \sqrt{27}\)

\(x\sqrt{3}= \pm \sqrt{9 * 3}\)

\(x\sqrt{3} = \pm 3\sqrt{3}\)

\(\implies x =\pm 3\)

Answer 4

thank you