Question

SQRT2X+4-SQRTX=2

Answer 1

\[\sqrt{2x+4}-\sqrt x=2~~?\]

Answer 2

Notice right away that and \(x\) that satisfies \(x<-2\) and \(x<0\), or simply just \(x<0\) will not be solutions.
\[\begin{align*}\sqrt{2x+4}&=\sqrt x+2\\
2x+4&=x+4\sqrt x+4\\
x&=4\sqrt x\\
x^2&=16x\\
x^2-16x&=0\\
x(x-16)&=0\\
x&=0,~16
\end{align*}\]
Neither solutions are negative, so both work.