Question

Give that log 4=0.6061, log 9=0.9542, and log 12=1.0792 evaluate each logarithmn Problem: log 108,000

Answer 1

108000 = 108 x 1000

= 9 x 12 x 1000

and 1000 = 10^3

and I'd assume you are looking at base 10 logs....

hope it helps

Answer 2

So, you would multiple log9 times log 12? Then plus 10^3?

Answer 3

\[\huge \log (108000) = \log(9\times 12 \times 10^3)\]\[\huge\implies \log 9 + \log 12 + \log 10^3\]

Answer 4

and it end up as

\[\log(9) + \log(12) + 3\log(10) = \log(9) + \log(12) + 3\]