Question

A force of 16.0 newtons is sufficient to set a box that is at rest into motion. If the coefficient of static friction is 0.380, what is the normal force acting on the box?

Answer 1

use F=ur
F=16 N
u=0.380 solve for r

Answer 2

let the normal force = N
the coefficient of static friction = μ
16 = μ N

N=16/0.38
N = 42.1 Newton