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An auditorium has 20 rows with 10 seats in the first row, 12 in the second, 14 in the third row, and so forth. How many seats are in the auditorium???
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I know that the answer is 580 but i want to know how to solve it using sequences
1. Plot the points in the form \((n, s)\) Where n = row and s = number of seats in the corresponding row (1, 10) (2, 12) (3, 14) (4, 16) and so on 2. Note the relationship between n and s 3(1) + 7 = 10 3(2) + 6 = 12 3(3) + 5 = 14 3(4) + 4 = 16 and so on 3. Notice that the formula becomes \(3n + 8 - n = s\) Or simply: (2n + 8 = s\) 4. Take the sum: \[\sum_{n=1}^{20}(2n + 8)\]
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