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(____)^2 = (cscx - 1)(cscx + 1)
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fill in the blank.
use the identity \[\csc ^2x-\cot ^2x=1\]
I dont know how to.
istnt it (cot)^2
\[\csc ^2x-1=\cot ^2x\]
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isn't what cot^2?
\[\left( a+b \right)\left( a-b \right)=a^2-b^2\]
a=csc x,b=1
oh so the answer is cot^2?
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