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Mathematics 7 Online
OpenStudy (anonymous):

The calculus of inverse functions >_> Ok so, I'll admit, I never fully understood this, it just seems like guess and check to me. The problem..

OpenStudy (anonymous):

\[f(x)=2x+cosx\] find \[(f ^{-1})'(1)\]

OpenStudy (anonymous):

I understand it's one - to - one because \[f'(x)=2-sinx>0\], so f is increasing.

OpenStudy (primeralph):

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