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OpenStudy (anonymous):
Can someone check my answer? I have to evaluate the following integral: (top limit) pi/9; (bot limit) 0: integral itself: x (tan^2) (3x) dx. My answer is: [6(sqrt of 3) pi- pi^2 - 9 ln(4) ] / 162 ?? If this is not right can someone show me how to get it. I missed class :/
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OpenStudy (cwrw238):
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