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MEDALS FOR THE BEST ANSWER! PLEASE HELP! Solve the quantity x minus 5, end quantity, over x, minus 1, equals the quantity x plus 3, end quantity, over x.
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\[\frac{x-5}{x-1}=\frac{x+3}{x}\] is my guess
"cross multiply" and start with \[x(x-5)=(x-1)(x+3)\] and solve the resulting quadratic equation
which isn't *really* a quadratic at all...
good point
ok thank u!! @mtbender74 @satellite73
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yw
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