Question

Suppose a_n = 3 a_{n-1} + 5 a_{n-2} + 5 a_{n-3} and a_4 = -24, a_5 = -77, and a_6 = -366. Find a_1, a_2, and a_3.

Answer 1

you can work backwards here. Since you know a4, a5, and a6 already, set up the equation with an being a6 and solve for a_n-3 (or a3)

Answer 2

repeat step with a_5, now that you know what a_3 is, you can find a_2. After that, find a_1 with the same procedure

Answer 3

still need help?