Question

the distance a spring stretches varies directly as the amount of force applied to the spring. If a force of 5 lb is required to stretch 2 in, what force is required to stretch the spring 5in

Answer 1

where are you stuck?

Answer 2

\[F=kx\\
5=2k~~\Rightarrow~~k=\frac{5}{2}\]
Now find the force \(F\) when \(x=5\):
\[F=\frac{5}{2}\times5=\cdots\]