Question

A 1600kg car is traveling along a straight road at 20m/s . Two seconds later its speed is 24m/s .

Answer 1

Ok. What's the rest of the question?

Answer 2

the acceleration is 24-20/2 = 2m/s^2
The force applied is constant, and it is 1600 * 2 = 3200N
The work the car used is F*d. d = V(initial) * t + 1/2 at^2 = 44, so work is 3200 * 44 = 140800 J, or 140 kJ

Answer 3

That's probably one of the thing you're looking for right? :)