Question

What is the distance between P(0, 14) and Q(5, -2)?

Answer 1

\(\LARGE\color{blue}{ \bf distance~=~\sqrt{(y_1-y_2)^{2}+(x_1 - x_2)^{2}} }\)

Answer 2

plug in your coordinates into the above formula, as

x1=0 x2=5
y1=14 y2=-2

Answer 3

I putt that formula in my TI-nspire and it gave me 7.2111 but my options are
A the square root of 281
B 13
C the square root of 171
D 14

Answer 4

\(\LARGE\color{blue}{ \bf \sqrt{(y_1-y_2)^{2}+(x_1 - x_2)^{2}} }\)


\(\Large\color{blue}{ \bf \sqrt{(5-(-2)~~)^{2}+(0 -14)^{2}} }\)


\(\Large\color{blue}{ \bf \sqrt{(5+2)^{2}+(0 -14)^{2}} }\)


\(\Large\color{blue}{ \bf \sqrt{(7)^{2}+( -14)^{2}} }\)


\(\Large\color{blue}{ \bf \sqrt{49+196} }\)


\(\Large\color{blue}{ \bf \sqrt{245} }\)