A fantasy board game makes use of four dice. The first is a standard 6-faced die, the second die has 4 faces, and the other two have 10 faces each. If all the dice are thrown together and their combination dictates a certain outcome of the game, how many possible outcomes exist?

Question

jim_thompson5910 · Answer

1st die: 6 outcomes
2nd die: 4 outcomes
3rd die: 10 outcomes
4th die: 10 outcomes


Each die is independent of one another, so we can multiply them out to get: 6*4*10*10 = 24*100 = 2400


There are 2,400 different outcomes for the 4 dice