A container has 50 electronic components, of which 10 are defective.
If 8 components are drawn at random from the container, what is the probability that exactly 3 of them are defective?

A-0.147
B-0.203
C-0.300
D-0.375
E-0.750

Question

A container has 50 electronic components, of which 10 are defective.
 If 8 components are drawn at random from the container, what is the probability that exactly 3 of them are defective?

A-0.147
B-0.203
C-0.300
D-0.375
E-0.750

kropot72 · Answer

The probability of a component being defective is 10/50 = 0.2.
$$P( out\ of\ 8\ defective)=8C3\times(0.2)^{3}\times(0.8)^{5}=you\ can\ calculate$$