Question

Please help me solve (x^2y^2/x^3y^7)^-2

Answer 1

well simplify the terms inside the brackets...

same base, subtract the powers.... when dividing, leave the answers in index form

\[(x^{2 -3}y^{2 - 7})^{-7}\]

next apply the power of a power law.. multiply the powers

\[(x^a)^b = x^{a \times b}\]

so the problem can be written as

\[(x^{2 - 3})^{-7} \times (y^{2 - 7})^{-7}\]

do the calculations of x and y... they should be both positive powers in the answer...

hope it helps