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inverse of g(x)=x-1/4?
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find \[\frac{ 1 }{ g(x)}\]
g(x)=(4x-4)/4
now 1/g(x)=inverse of g(x)=4/(4x-4)=1/(x-1)
so g-1(x)=4x-4
no g(x)=\[(4x-4)/4\]
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oh 4x+1
so \[g ^{-1}(x)=4/(4x-4)=1/(x-1)\]
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