PLEASE HELP WITH THIS? calculate the listed element for the product matrix???
i have the answers to all the problems on the page, except find c23
can anyone help me find c23? my mom helped me with c33 but now im stuck again
\[ C_{23 } = \left[ \begin{array}{ccc} 3&4&0\end{array} \right] \left[ \begin{array}{ccc} 9 \\ 1\\ -3 \end{array} \right] \]
c23 will be 31..!!!
just take the dot product of vectors in 2nd row and 3rd column of respective matrices ^
multiply 1st entry of row of 1st column to the 1st entry of 3rd column of 2nd matrix ,then multiply thier 2nd entries and then 3rd add them up all ..use usual symbols of + and - come with ,ultiplication..!!!
thank both of you so much!!!
u wc...!!!
and c33 will be -98..!!!
@zaibali.qasmi can you help with 2 more? theyre my last problems, and i have half of the one done
yeah y not..!!!
i have part b of the first one done, i got 6*4-((-8)*(-3)) 24-(24) 0 and for part A i got this far 4*2-(8*(-3))=8+24=32 but i dont know how to find the inverse.
just wait..replying...!!!
herre invers exists for matrix(a) but not for (b)...because (b) is a singular matrix and it is essential property to be non-singular for having an inverse..!!!wait i told you in nxt how to find inverse..!!!
okayyy
\[A^{-1}=\frac{ A^{T} }{ Adj A }\] use this reelation to find inverse...the easiest way..!!!
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