Ask your own question, for FREE!
Mathematics 9 Online
OpenStudy (tootsi123):

what is AB?

OpenStudy (tootsi123):

OpenStudy (anonymous):

4, I think. I'm not the best at this stuff. Is this area or perimeter?

OpenStudy (anonymous):

mmmmm I'm not sure but here i think you need vectors rules !!

OpenStudy (anonymous):

Is there an answer choice?

OpenStudy (tootsi123):

@Vivid this is finding the length of the diagonal.

OpenStudy (anonymous):

like you first find the length of string required to connect the platforms to the nearest !! and so on

OpenStudy (anonymous):

4.1

OpenStudy (anonymous):

how you get it ??

OpenStudy (anonymous):

w2 + h2 2=square

OpenStudy (tootsi123):

Okay so here are the answers, sqrt of 53, 5, 2 sqrt of 10, and 2 sqrt 6

hero (hero):

Use the Pythagorean Theorem in 3D: \[d = \sqrt{x^2 + y^2 + z^2} \]

OpenStudy (tootsi123):

@Hero so 4^2+6^2+1^2

OpenStudy (tootsi123):

right

hero (hero):

Now take the square root of that to get d

OpenStudy (tootsi123):

I got 7. is that right so far

OpenStudy (tootsi123):

@Hero

OpenStudy (loser66):

|dw:1400085400033:dw|

OpenStudy (tootsi123):

thank you how did u get that do u care to explain

OpenStudy (loser66):

I just inherit what you do. \(\sqrt{4^2+6^2+1^2}=\sqrt{53}\)

OpenStudy (anonymous):

Basically this formula is taken from the fact that yu can see triangles there with 90 degrees corners.

OpenStudy (tootsi123):

okay but when i added all of them i got 49? what did i do wrong

hero (hero):

\(4^2 = 4 \times 4 = 16\) \(6^2 = 6 \times 6 = 36\) \(1^2 = 1 \times 1 = 1\) \[16 + 36 + 1 = 10 + 6 + 30 + 6 + 1\] \( \space= 10 + 30 + 10 + 2 + 1 \\= 50 + 3 \\= 53\)

OpenStudy (tootsi123):

okay

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!