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Mathematics 17 Online
OpenStudy (anonymous):

What are the steps to figure this question out (2u+v)^10

OpenStudy (anonymous):

Do you want to expand it?

OpenStudy (anonymous):

to the 7th term

OpenStudy (anonymous):

(2u+v)^10 = (2u+v)^7 (2u+v)^3

OpenStudy (anonymous):

(2u+v)^7 * (2u+v)^3 = (2u+v)^(7+3) = (2u+v)^10. Is that what you want?

OpenStudy (anonymous):

I tried that way and the answer still didn't come out correct it's finding the 7th term of the binomial

OpenStudy (anonymous):

Or do you want to foil it?

OpenStudy (anonymous):

So you have to foil it then, and find the 7th term.

OpenStudy (anonymous):

1024 x^10+5120 x^9 y+11520 x^8 y^2+15360 x^7 y^3+13440 x^6 y^4+8064 x^5 y^5+3360 x^4 y^6+960 x^3 y^7+180 x^2 y^8+20 x y^9+y^10 Here is is foiled, the 7th term is 3360x^4 y^6

OpenStudy (anonymous):

Thank you! That was the answer! There is just more confusing way to do it in the book. I appreciate it!

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