Question

help?

Answer 1

factor and cancel like crazy

Answer 2

haha i shall

Answer 3

I'm scared i don't wanna fail

Answer 4

\[\large \frac{(4x-12)(x+3)(x^2-25)}{(x^2-9)(5x^2-25x)16}\]
\[\large \frac{4(x-3)(x+3)(x+5)(x-5)}{(x+3)(x-3)5x(x-5)16}\]

Answer 5

cancel your brains out, and you are left only with \[\frac{x+5}{20x}\]

Answer 6

okay okay and then do i distribute?

Answer 7

oh no!
if you distribute, you get the same thing you started with
cancel common factors is the idea for this question

Answer 8

ohhh okay lol thank you!!!!! thank you! thank you! thank you!

Answer 9

yw