Ask your own question, for FREE!
Mathematics 11 Online
OpenStudy (lucaz):

ln(x)+1<0

OpenStudy (lucaz):

I'm looking for an interval.. I found 1/e < x

OpenStudy (anonymous):

backwards

OpenStudy (anonymous):

\[\ln(x)<-1\\ x<\frac{1}{e}\]

OpenStudy (lucaz):

thanks

OpenStudy (anonymous):

yw

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!