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Determine which ordered pair is a solution of \[y= x^{2}-2\]
(5,21), (-5,24), (-1,-1), (2,6)
@armorbeck
\[Y=X ^{2}-2\] y equals x to the power two minus two or negative two
just put the X and Y into the equation, for example plug in 21 for Y and 5 for X giving you \[21=5^{2}-2\]
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Thanks!!!!
if it turns out true then that will be your answer
Ah! Dangit!
(-1,-1) : (
yeap
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