Question

Solve by using the perfect squares method.

x2 + 8x + 16 = 0

A.
2

B.
–2

C.
–4

D.
4

Answer 1

\(x^2+bx+c=0\implies (x+\frac{b}{2})^2=-c+(\frac{b}{2})^2\)
solve for x

Answer 2

so \((x+4)^2=-16+4^2\) solve for x

Answer 3

or note \((a+b)^2=a^2+2ab+b^2\) for you \(a=x, b=4\)