Help please ! In triangle ABC, C is a right angle. If B= 31 degrees and C =14, what are the measures of the remaining sides and angles? round answers to the nearest hundredth.
i think we need a picture are B and C angles? that is not possible maybe one is an angle and one is a side? or are they both sides? need some more info here
C= 14 is a side. C is a right angle.
|dw:1400116427248:dw|
like that?
I believe so I was just trying to draw it [:
ok let me label a couple things
|dw:1400116520255:dw|
then \[\sin(31)=\frac{b}{14}\] so \[b=14\sin(31)\]you will need a calculator to compute that
also \[\cos(31)=\frac{a}{14}\]so \[a=14\cos(31)\] again a calculator
So both A and B will equall = 12?
oops is see my mistake lol
not likely no
b= 7.2 a= 12
yeah that looks good \[b=7.2,a=12\]
So those are the sides? how would I do the angles?
There's still one more step.. How do I find Angle A @sattellite73?
the angle of any right triangle have to add up to 180
i meant ANY TRIANGLE (doesn’t have to be a right triangle)
180- 90 - 31 ?
to find your missing angle, compute \[180-90-31\]
yup
59 degrees. Thank you [:!
yw
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