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If the length of one side of a square is 4x-3, find the area in terms of x.
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they really stretch for these word problems don't they? what they want is for you to compute \[(4x-3)^2\]
We computed that \[16x^{2}-24x+9\] but what does that tell us?
Using the quadratic formula x will = 0.75 and when you plug that back into the original 4x-3 will equal 0 and 0 X 0 = 0 so is this unsolvable?
The problem wasn't an inequality. Obviously if you set the equation equal to 0, solve it, and then plug the values back in, you will always get 0.
So must I say x is something greater than 0.75?
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