Mathematics
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OpenStudy (tootsi123):
x =
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OpenStudy (tootsi123):
OpenStudy (tootsi123):
@kx2bay can u help me with this one to pleasse
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
here is a hint ;)
OpenStudy (tootsi123):
okay so that makes since. it would then be. but wait now i'm comfused because i don't know what p =
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OpenStudy (anonymous):
giving u another hint ;)
OpenStudy (tootsi123):
\[P4timesP5=P3timesPX?\]
OpenStudy (anonymous):
u ok now to continue on ur own ?
show me that x = 9 , can you?
OpenStudy (anonymous):
ur above answer is wrong, please correct and write again
OpenStudy (tootsi123):
Alright. so would it then be X^2=3(5*4)
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OpenStudy (anonymous):
no u r guessing now, forget about the previous question u had, this is bit different, refer to my first hint , the formula is there
OpenStudy (tootsi123):
okay
OpenStudy (anonymous):
PQ * PR = PS * PT
what is PQ, PR, PS, PT ?
OpenStudy (tootsi123):
PQ=4
PR=5
PS=3
PT=X
OpenStudy (tootsi123):
So 4*5=3X
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OpenStudy (anonymous):
look at PR again,
PR = PQ + QR, right ?
Now do the same for PT, can you?
OpenStudy (tootsi123):
so PT=PS+SP which is also X=3+3 right?
OpenStudy (anonymous):
PT = 3 + x
and PR = 4 + 5
so you end up with
4 * 9 = 3 (3 +x)
36 = 9 + 3x
3x = 27
x = ?
OpenStudy (tootsi123):
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