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Mathematics 19 Online
OpenStudy (tootsi123):

x =

OpenStudy (tootsi123):

OpenStudy (tootsi123):

@kx2bay can u help me with this one to pleasse

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

here is a hint ;)

OpenStudy (tootsi123):

okay so that makes since. it would then be. but wait now i'm comfused because i don't know what p =

OpenStudy (anonymous):

giving u another hint ;)

OpenStudy (tootsi123):

\[P4timesP5=P3timesPX?\]

OpenStudy (anonymous):

u ok now to continue on ur own ? show me that x = 9 , can you?

OpenStudy (anonymous):

ur above answer is wrong, please correct and write again

OpenStudy (tootsi123):

Alright. so would it then be X^2=3(5*4)

OpenStudy (anonymous):

no u r guessing now, forget about the previous question u had, this is bit different, refer to my first hint , the formula is there

OpenStudy (tootsi123):

okay

OpenStudy (anonymous):

PQ * PR = PS * PT what is PQ, PR, PS, PT ?

OpenStudy (tootsi123):

PQ=4 PR=5 PS=3 PT=X

OpenStudy (tootsi123):

So 4*5=3X

OpenStudy (anonymous):

look at PR again, PR = PQ + QR, right ? Now do the same for PT, can you?

OpenStudy (tootsi123):

so PT=PS+SP which is also X=3+3 right?

OpenStudy (anonymous):

PT = 3 + x and PR = 4 + 5 so you end up with 4 * 9 = 3 (3 +x) 36 = 9 + 3x 3x = 27 x = ?

OpenStudy (tootsi123):

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