Question

log(2^x+3)=3 I need help solving this I'm confused

Answer 1

What is the base of the logarithm? 10?

Answer 2

idk that's all the question said

Answer 3

Base 10 can probably be assumed, as the subscript is usually omitted.
\[\begin{align*}\log(2^x+3)&=3\\
10^{\log(2^x+3)}&=10^3\\
2^x+3&=1000\\
2^x&=997\\
\log_2 2^x&=\log_2 997\\
x\log_2 2&=\log_2997\\
x&=\log_2997\end{align*}\]