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help simplify the complex fraction please
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n-3/n^2+6n+8/n+1/n+2
@Hero
@Yttrium
can you rewrite the fraction more properly?
n-3 ------ n^2+6n+8 ------ n+1 ------ n+2
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i know the answer just need to know how to get it
\[\frac{ n-3 }{ (n+4)(n+1) }\]
\[\frac{ n-3 }{ n^2+6n+8 }\frac{ n+2 }{ n+1 } = \frac{ n-3 }{ (n+2)(n+3) }\frac{ n+2 }{ n+1 }=\frac{ n-3 }{(n+4)(n+1) }\]
^solution
okay thank you so much!!
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medal?
i did?
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