Question

@Gegomohamed

Answer 1

wait :D

Answer 2

ok :)

Answer 3

it will be A tell you how

Answer 4

a(bx+2)=cx-12
abx+2a=cx-12

*collect x together and numbers together*
abx-cx=-12-2a

*take x common factor*
x(ab-c)=-12-2a

*divided by (ab-c)*
\[x=\frac{ -12-2a }{ ab-c }\]

Answer 5

get or no ??

Answer 6

ohhh yeah i got it :D

Answer 7

i need help with this one ---> Is the relation {(3, 5), (–4, 5), (–5, 0), (1, 1), (4, 0)} a function? Explain. Type your answer below.

Answer 8

@Gegomohamed