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Physics 13 Online
OpenStudy (anonymous):

Can someone check my work? Not sure what I did wrong for this problem on forces. Thank you!

OpenStudy (anonymous):

OpenStudy (anonymous):

I got an acceleration of 1.15 m/s^2. See the photo.

OpenStudy (vincent-lyon.fr):

It is a bit difficult to follow you work because you are mixing litteral and numerical values from the start. Using the energy method, I find the same value for acceleration as Psi². \(a=g\dfrac{m_2\sin\theta-\mu_1m_1-\mu_2m_2\cos\theta}{m_1+m_2}\)

OpenStudy (vincent-lyon.fr):

Try to solve again after correcting these mistakes.

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