Ms. Jones invested $24,000 in two accounts, one yielding 6% interest and the other yielding 12%. If she received a total of $2,400 in interest at the end of the year, how much did she invest in each amount?
The amount invested at 6% was $

Question

Ms. Jones invested $24,000 in two accounts, one yielding 6% interest and the other yielding 12%. If she received a total of $2,400 in interest at the end of the year, how much did she invest in each amount? 
The amount invested at 6% was $

anonymous · Answer

$$.06x+.12(24,000-x)=2400$$ should do it

anonymous · Answer

where $x$ is the amount invested at $6\%$ so $24,000-x$ is the amount invested at $12\%$

anonymous · Answer

probably easier to solve if you remove the annoying decimals and start with 
$$6x+12(24,000-x)=240,000$$

savannah_noelle · Answer

Thank you! so x=8000?