Question

So lost...What is the current in a series circuit that has two resistors
(4.0 ohms and 7.5 ohms) and a power source of 9.0 volts?

Answer 1

for series connection resistences will add up so ur equivelent resistence is=(4+7.5)ohm=11.5
now the sircuit will look like
now simply
\[current=\frac{ voltage }{ resistence }\]