I need help i will fan and reward a metal for those who solve!!!!!!
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OpenStudy (anonymous):
whats the question
OpenStudy (anonymous):
What is the approximate area of the composite figure shown? Use three point one four for pi.
A rectangle that is twenty feet long and twelve feet wide has a semicircle attached to its right, twelve-foot side. So, the semicircle has a diameter of twelve feet.
one hundred twenty point five two square feet
two hundred ninety-six point five two square feet
three hundred fifty-three point zero four square feet
six hundred ninety-two point one six square feet
OpenStudy (anonymous):
Thx so much for your help!
OpenStudy (anonymous):
can u draw the coposit figure please
OpenStudy (anonymous):
|dw:1400274677171:dw| almost like that
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OpenStudy (anonymous):
but the left side of the circle is erased
OpenStudy (anonymous):
so like a half cylinder
OpenStudy (anonymous):
no its a 2d figure
OpenStudy (anonymous):
ok
1 sec
OpenStudy (anonymous):
o thank you!!!
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OpenStudy (anonymous):
ok first find the area of the rectangle L*W
OpenStudy (anonymous):
tht is 240
OpenStudy (anonymous):
keep that in mind u need it in a min
now u have to find the area of the circle sine they gave you the diameter (D) use
3.14*D
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
so then i would divide that by two and add thae two and i will get my answer
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OpenStudy (anonymous):
then divid that by 2 because it is half of a circle
last add your 2 areas togeather