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OpenStudy (anonymous):
2x(3x-4)=22
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OpenStudy (anonymous):
Uhmmm First step would be to distribute the 2x into the term inside the bracket: 2x(3x-4)=22 6x^2-8x=22 6x^2-8x-22=0 Now, you must common factor: 2(3x^2-4x-11)=0 Now you can factor the term in the brackets and you will get two x values :)
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