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Help with the second step? And is the first step right?
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so first find the common ratio r r = 2nd term/ 1st term = 3rd term/ 2nd term = ...so on
1.2/.8= 1.5 1.8/1.2= 1.5
yes r = 1.5 now use the general formula \(a_n = a_1 r^{n-1}\)
here you need 6th term! because starting is 0 hours so plug in n =6 !
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a_n=a_1 r^n-1 a_n=0.8 1.5^n-1 a_n=0.8 1.5^6-1 a_n=0.8 1.5^5 a_n=0.8 (7.59375) a_n=6.075
Is that right?
correct :)
but thats the final number the formula, which is asked is is \(\Large a_n = 0.8 \times (1.5)^{n-1} \)
I know lol thanks!
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welcome ^_^
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