Question

help solving these trig equations?

Answer 1

\[\cos^2x=cosx\]

Answer 2

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Answer 3

cos^2 - cos = 0

cos(cos - 1) = 0

cos x = 0 cos x = 1

x = pi/2, 3pi/2 x = 0

Answer 4

\[cosxtanx=\frac{ 1 }{2 }\]

Answer 5

Post on a new thread and show your work. You showed no work on this, first one. It's your turn.