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Mathematics 14 Online
OpenStudy (anonymous):

A=Pe^rt question below↓↓↓↓↓

OpenStudy (anonymous):

OpenStudy (kropot72):

Substituting the given values into the equation we get: \[4000=Pe ^{0.05\times2}=Pe ^{0.1} ......(1)\] Rearranging equation (1) to find the required principal we get: \[P=\frac{4000}{e ^{0.1}}=you\ can\ calculate\]

OpenStudy (anonymous):

Thank you!

OpenStudy (kropot72):

You're welcome :)

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