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\[\frac{ m-3 }{3m-9 }\]
@Jesstho.-.
You have to cross cancel
Then it'll be like m-3 3m-9 m-3 3(m-3) m-3 in numerator and denominator will be cancelled with each others
Just first try to factor out 3 from denominator so we have 3(m - 3) so we get (m - 3) ------ 3(m - 3) now just cancel common term from numerator & denominator .. we get 1/3
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So 1/3
Thanks guys :)
You're welcome
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