Question

how to solve these trig equations?

Answer 1

ima write them right now

Answer 2

\[\sin2x=1\]

Answer 3

\[\sin 2x=1=\sin \frac{ \pi }{ 2 }=\sin \left( 2n \pi+\frac{ \pi }{ 2 } \right)\]
\[2 x=2 n \pi +\frac{ \pi }{ 2 },x=?~ where~ n~ is~ an~ integer.\]

Answer 4

\[\sin2x-1=0\]