If sin Θ = negative square root 3 over 2 and π

Question

If sin Θ = negative square root 3 over 2 and π < Θ < 3 pi over 2, what are the values of cos Θ and tan Θ?


cos Θ = negative 1 over 2; tan Θ = square root 3

 cos Θ = negative 1 over 2; tan Θ = −1

 cos Θ = square root 3 over 4; tan Θ = −2

 cos Θ = 1 over 2; tan Θ = square root 3

anonymous · Answer

@ganeshie8

campbell_st · Answer

this is a 3rd quadrant question where tan is positive, sin and cos are negative... 

use the given information to find the missing side

|dw:1400364118035:dw|

find a... using pythagoras it will be negative... 

then you can find tan and cos... 

hope it helps