The sum of three numbers is 131. The second of three numbers is seven more than twice the first. The third number is 12 less than the first. What equation can be used to solve the problem?
A. x + x + x = 131
B. x + (x + 7) + (x – 12) = 131
C. x + (2x + 7) + (x – 12) = 131
D. x + (2x + 7) – 12 = 131

Question

The sum of three numbers is 131. The second of three numbers is seven more than twice the first. The third number is 12 less than the first. What equation can be used to solve the problem?
A. x + x + x = 131
B. x + (x + 7) + (x – 12) = 131
C. x + (2x + 7) + (x – 12) = 131
D. x + (2x + 7) – 12 = 131

anonymous · Answer

Establish what the 2nd and 3rd numbers are relative to the 3rd.
1st number: x
3rd number: x -12
2nd number: 2x + 7

C.