Question

C(n)=10n+20
inverse function
A. N(c)= c+10/20

B. N(c)= c-10/20

C. N(c)= c-20/10

D. N(c)= c+20/10

Answer 1

Solve the function for n:
n = (C(n) - 20)/10
Replace n with N(c) and and C(n) with c:
N(c) = (c - 20)/10
C

Answer 2

thank you for explaining to me