how does the galvanometer respond when the switch in the circuit is opened in a primary coil

Question

rane · Answer

@sidsiddhartha

sidsiddhartha · Answer

when the switch was closed there were some associated magnetic field now if u opened the switch then this magnetic field will be vanished and so as the magnetic field is vanished the pointer will move to the opposite direction due to a opposite torque

sidsiddhartha · Answer

this torque is known as deflection torque

anonymous · Answer

@sidsiddhartha  do we directly talk about magnetic field??

anonymous · Answer

Its better to say that when current flows through a circuit, the connected galvanometer affected by this current, and by this current deflection produced in the galvanometer...... due to interaction of current carrying coil ( present in the galvanometer) and magnetic field ( applied in the galvanometer) .. @sidsiddhartha

anonymous · Answer

Magnetic field apply the force on current carrying coil(present in the galvanometer), that causes the deflection of the needle of galvanometer.

rane · Answer

thanks both of u 
i understood the main principles

sidsiddhartha · Answer

yeah and this torque is directly prop to the current$$T \infty I$$

anonymous · Answer

yup thats it...